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6x^2-5x-38=0
a = 6; b = -5; c = -38;
Δ = b2-4ac
Δ = -52-4·6·(-38)
Δ = 937
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{937}}{2*6}=\frac{5-\sqrt{937}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{937}}{2*6}=\frac{5+\sqrt{937}}{12} $
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